Fluid MechanicsF_b = ρ_f g V

Buoyancy Simulator

Submerge objects of different densities in a fluid. See buoyant force, weight, and net force and predict whether objects float or sink.

Parameters
Object Density ρ_obj
kg/m³
Fluid Density ρ_fluid
kg/m³
Volume V

Common densities
Wood (pine)500 kg/m³
Water1000 kg/m³
Aluminium2700 kg/m³
Iron/Steel7874 kg/m³
F_buoyant98.10 N
F_weight58.86 N
F_net39.24 N
Submerged60.0 %
Status0 Floats

About Buoyancy and Archimedes' Principle

Archimedes' principle states that any object immersed in a fluid experiences an upward buoyant force equal to the weight of fluid displaced. This principle explains why ships float despite being made of dense steel, and why a stone sinks in water.

Archimedes reportedly discovered this principle while stepping into a bath and noticing the water level rise — leading to his famous exclamation 'Eureka!' ('I have found it!').

Key Variables

SymbolNameUnitDescription
ρ_objObject Densitykg/m³Mass per unit volume of the object
ρ_fluidFluid Densitykg/m³Mass per unit volume of the fluid
VObject VolumeTotal volume of the object
V_subSubmerged VolumeVolume of object below the fluid surface
F_bBuoyant ForceNUpward force from the displaced fluid
F_wWeight ForceNDownward gravitational force on the object
F_netNet ForceNF_b − F_w; positive = floats, negative = sinks
gGravitational accelerationm/s²Standard value 9.81 m/s²

Floating vs Sinking Condition

  • Floats: ρ_obj < ρ_fluid. Only part of the object is submerged. The submerged fraction is ρ_obj/ρ_fluid.
  • Neutral buoyancy: ρ_obj = ρ_fluid. The object floats at any depth without rising or sinking.
  • Sinks: ρ_obj > ρ_fluid. The net force is downward and the object accelerates toward the bottom.

Worked Example — Floating

A wooden block (ρ = 600 kg/m³, V = 0.01 m³) in fresh water (ρ_fluid = 1000 kg/m³):

\text{Fraction submerged} = \frac{\rho_{obj}}{\rho_{fluid}} = \frac{600}{1000} = 0.60\text{ (60%)}

At equilibrium, F_b = F_w exactly — the object floats with 60% submerged.

Worked Example — Sinking

An iron ball (ρ = 7874 kg/m³, V = 0.001 m³) in water (ρ_fluid = 1000 kg/m³):

💡The buoyant force depends only on the displaced fluid volume, not on the object's density. A hollow steel ship floats because its average density (including air inside) is less than water.

Key Formulas

Archimedes' Principle (Buoyant Force)

Weight Force

Net Force

Floating Equilibrium (Submerged Fraction)

FormulaDescriptionNotes
F_b = ρ_f g V_subBuoyant forceρ_f = fluid density, V_sub = submerged volume
F_w = m g = ρ_obj V gWeight of objectTotal weight, not just submerged portion
F_net = F_b − F_wNet vertical forcePositive upward; zero at floating equilibrium
V_sub/V = ρ_obj/ρ_fluidFraction submergedOnly valid when floating (ρ_obj < ρ_fluid)
ρ = m/VDensityKey property determining float/sink behaviour
When ρ_obj = ρ_fluid the object is neutrally buoyant — it will remain at whatever depth it is placed. Submarines achieve this by pumping water in or out of ballast tanks.

Frequently Asked Questions

Why does a ship made of steel float?

A steel ship is hollow — it encloses a large volume of air. The average density of the ship (steel + air) is less than water. What matters is not the density of the material but the average density of the entire object including any air spaces.

Does the shape of the object affect buoyancy?

No — only the volume of fluid displaced matters, as Archimedes' principle states. F_b = ρ_fluid × V_submerged × g regardless of shape. Shape does affect stability (tendency to tip over), but not the magnitude of the buoyant force.

What happens if the fluid is denser, like the Dead Sea?

The Dead Sea has salinity around 34%, giving ρ ≈ 1240 kg/m³. Because the fluid is denser, the required submerged fraction ρ_obj/ρ_fluid is smaller — you float higher. That is why people float effortlessly in the Dead Sea.

What is neutral buoyancy and how do submarines use it?

Neutral buoyancy means ρ_obj = ρ_fluid, so F_net = 0. The object neither rises nor sinks. Submarines achieve this by pumping seawater into or out of ballast tanks, changing their average density to match the surrounding water at a desired depth.

Does buoyancy work in air?

Yes! Helium balloons and hot-air balloons use buoyancy in air. Air has ρ ≈ 1.2 kg/m³. Helium (ρ ≈ 0.17 kg/m³) is less dense than air, so a helium-filled balloon experiences a net upward buoyant force and rises.